If f (x) = one-ninth x minus 2, what is Superscript negative 1 Baseline (x) = one-ninth x + 2 f Superscript negative 1 Baseline (x) = negative 2 x + one-ninth

f⁻¹(x)  = 9(x+2)

Step-by-step explanation:

Given the function

f(x) = 1/9 x - 2

We are to find the inverse of the function

Let y = f(x)

y = 1/9 x - 2

Replace y with x

x = 1/9 y - 2

Make y the  subject of the formula

1/9 y = x + 2

Multiply through by 9

y = 9(x+2)

Hence the inverse of the function is 9(x+2)

f^-1x=9x+18

Step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.