Is (3, –2) a solution for the following system? Yes or No x + y = 1 2x + 3y = 1

NO

Step-by-step explanation:

Plugging in 3 for X and -2 for Y

X + Y = 12X _ 3Y = 1

3 + -2 = 12*3 + 3 * -2 = 1

1 = 36 + 3 * -2 = 1

1 = 36 + -6 = 1

1 = 30 = 1

So NO, (3, -2) is not a solution.

pooopoopopoopop

step-by-step explanati∵∵∴∴on:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.