Find the P-value for a test of the claim that more than 60% of the people following a particular diet will experience increased energy (H1: p > 0.6). Of 100 randomly selected subjects who followed the diet, 70 noticed an increase in their energy level. 2.041 1.5486 1.2743 2.536

The p-value of the test is 0.0207.

Step-by-step explanation:

Test of the claim that more than 60% of the people following a particular diet will experience increased energy (H1: p > 0.6).

The null hypothesis is:

The alternate hypothesis is:

The test statistic is:

In which X is the sample mean, is the value tested at the null hypothesis, is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that

Of 100 randomly selected subjects who followed the diet, 70 noticed an increase in their energy level.

This means that

Test statistic:

P-value of the test:

The p-value of the test is the probability of finding a sample proportion of at least 0.7, which is 1 subtracted by the p-value of z = 2.04.

Looking at the z-table, z = 2.04 has a p-value of 0.9793

1 - 0.9793 = 0.0207

The p-value of the test is 0.0207.

good luck!

cutie~

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it