A firework rocket consists of a cone stacked on top of a cylinder, where the radii of the cone and the cylinder are equal. The diameter of the cylindrical base of the rocket is 8 in and the height of the cylinder is 5 in, while the height of the cone is 3 in. Calculate the surface area of the rocket. Leave your answer in terms of π.

188π in^2

Step-by-step explanation:

Surface area of the rocket = surface area of the cone + surface area of the cylinder

Surface area of a cone = πr(r+h^2+r^2)

r = 8/2 = 4 in

4π( 4 + 3^2 + 4^2) =

4π ( 4 + 9 + 16) = 116π in^2

Surface area of a cylinder = 2πrh+2πr^2

(2 x n x 4 x 5) + (2 x n x 16)= 72π in^2

116 + 72 = 188π in^2

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1