Find two numbers if their sum is 3/5 and their difference is 7 1/5

A = 3 + 9/10

B = -(3 + 3/10)

Step-by-step explanation:

We have two numbers, A and B, such that:

A + B = 3/5

A - B = 7 + 1/5

To solve this, we first need to isolate one of the variables in one of the equations, I will isolate A in the first equation:

A = 3/5 - B

Now we can replace this in the other equation:

A - B = 7 + 1/5

(3/5 - B) - B = 7 + 1/5

3/5 - 2*B = 7 + 1/5

-2*B = 7 + 1/5 - 3/5

-2*B = 7 - 2/5 = 35/5 - 2/5 = 33/5

B = -(33/5)/2 = -33/10 = - 30/10 - 3/10 = -3 - 3/10 = -(3 + 3/10)

Now that we know the value of B, we can use the equation

A = 3/5 - B

To find the value of A:

A = 3/5 - ( -(3 + 3/10))

A = 3/5 + (3 + 3/10)  = 6/10 + 3 + 3/10 = 3 + 9/10

The numbers are:

A = 3 + 9/10

B = -(3 + 3/10)

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: