Help? It says find the surface area of the triangular prism, and the base is an isosceles triangle

Given:

The figure and dimensions of the triangular prism.

The base is an isosceles triangle

To find:

The area of the triangular prism.

Solution:

The area of a triangle is:

The base of the triangle is 24 cm and the height is 35 cm. So, the area of a triangular base (in sq. cm) is:

The bases of the triangular prism are same. So, the area of the other triangular base is sq. cm.

The sides of the base triangle are 37 cm, 37 cm and 24 cm. So, the perimeter of the base triangle is:

Now, the curved surface area of the prism is:

Where, P is the base perimeter and h is the height of the prism.

The base perimeter of the triangular prism is 98 cm and the height is 48 cm. So, the curved surface area is:

Now, the total  area of the triangular prism is:

Therefore, the area of the given triangular prism is 5544 sq. cm.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°