Mathematics, 13.05.2021 07:00, valensanta2005

1.The total cost of 2 baseballs and 4 footballs is $30.00. The total cost of 8 baseballs and 1 necklace is $37.50. Let b represent the number of baseballs and f represent the number of footballs. This situation can be represented by the
system of equations below.
2b + 4 = 30.00
8b+ f = 37.50

Answers: 2

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1.The total cost of 2 baseballs and 4 footballs is $30.00. The total cost of 8 baseballs and 1 necklace is $37.50. Let b represent the number of baseballs and f represent the number of footballs. This situation can be represented by the system of equations below. 2b + 4 = 30.00 8b+ f = 37.50

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1.The total cost of 2 baseballs and 4 footballs is $30.00. The total cost of 8 baseballs and 1 necklace is $37.50. Let b represent the number of baseballs and f represent the number of footballs. This situation can be represented by the
system of equations below.
2b + 4 = 30.00
8b+ f = 37.50