In a class of 25 students, 5 have a cat and 9 have a dog. There are 3 students who have a cat and a dog. What is the probability that a student has a cat given that they do not have a dog?

Gotta be d the music of previous eras

The correct answer is -3.9> -4.5 gucci playa

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.

If this is the question f(x)= -x2 +4x-3 f(-1)= )2 +4 (-1)-3 =2-4-3 f(-1) =-5