Simplify as far as possible.
1
3cos (180° + x)sin (360° - X)
sin (360° + x)cos (180° - x)​

See below

Step-by-step explanation:

cos (180 + x) = - cos x

sin (360 + x) = sin x

sin 360 - x) = -sin x

cos (180 - x) = - cos x

3cos (180° + x)sin (360° - X) = -3cos x (- sin x) = 3 cosx sinx

sin (360° + x)cos (180° - x)​ = sin x (- cos x) = -sinx cosx

3cos (180° + x)sin (360° - X)sin (360° + x)cos (180° - x)​

= 3 cosx sinx (-sinx cosx) = -3 (sin x)^2 (cos x)^2

I am not sure what the question really is, but hopefully the above can steer you in the right direction.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a