Consider a circle with center (2,-3) that passes through the point (5,4). What is the equation of the described circle?
A) (x - 2)^2 + (y + 3)^2 = 58
B) (x - 2)^2 + (y + 3)^2 = 68
C) (x + 2)^2 + (y - 3)^2 = 58
D) (x + 2)^2 + (y - 3)^2 = 68

If the circle passes through the point (6,5), what is the equation of the new circle with the same center?
A) (x + 2)^2 + (y - 3)^2 = 80
B) (x + 2)^2 + (y - 3)^2 = 90
C) (x - 2)^2 + (y + 3)^2 = 80
D) (x - 2)^2 + (y + 3)^2 = 90

Part A: A. Part B: C

Step-by-step explanation:

Substitute the number into the equation of circle: (x-h)^2 + (y-k)^2=r^2

h and k are 2, -3 so you will need to change their signs.

The final thing you will do is to find the distance of center to point. Using distance formula and you will able to find the radius. Square your radius then the result will be there

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.