You roll a standard number cube 7 times Assume that each number is equally likely to come up each time you roll To the nearest tenth of a percent the probability that number less than 3 comes up exactly 4 of the 7 times

0.4%

Step-by-step explanation:

If we are looking to have a number less than 3 rolled 4 out of 7 times.

Our winning numbers are 1 and 2. Our losing numbers are 3, 4, 5, and 6.

This means that our winning percentage is 33.3% and our losing percentage is 66.6%.

We need to multiply these numbers together taking our number of rolls into account.

.333 * .333 * .333 * .333 * .666 * .666  * .666 = 0.0036

answer: i think one of the answer is $150 and $300?

step-by-step explanation:

if e is the midpoint of bd, then bd is 14.

step-by-step explanation: