The North Slope clothing store chain estimates that the annual demand for its most popular cotton sweater has a mean of approximately 26,000 units each year with a standard deviation of 2,000. North Slope buys these sweaters from a manufacturer located in Canada. The fixed cost of placing an order for this particular product is $200. North Slope pays $10 for each cotton sweater. The company's cost of capital is 11%, and the cost of storing a sweater for one year is $1.10. While North Slope prefers not to backlog customer demand, management of the company believes that it can afford to run out of sweaters on an occasional basis. The company estimates that the shortage cost per sweater per year is about $20. You may assume that lead time is 2 weeks. Find the optimal (r, Q) policy by minimizing North Slope's expected annual cost, and use it to answer the following questions: North Slope should place an order for sweaters (round to nearest whole number), whenever inventory drops to a level at or below sweaters. The expected annual cost of this policy is $ ?

The North Slope clothing store chain estimates that the annual demand for its most popular cotton sweater has a mean of approximately 26,000 units each year with a standard deviation of 2,000. North Slope buys these sweaters from a manufacturer located in Canada. The fixed cost of placing an order for this particular product is $200. North Slope pays $10 for each cotton sweater. The company's cost of capital is 11%, and the cost of storing a sweater for one year is $1.10. While North Slope prefers not to backlog customer demand, management of the company believes that it can afford to run out of sweaters on an occasional basis. The company estimates that the shortage cost per sweater per year is about $20. You may assume that lead time is 2 weeks. Find the optimal (r,Q) policy by minimizing North Slope's expected annual cost, and use it to answer the following questions:

Step-by-step explanation: hope this helps

b

step-by-step explanation:

b

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!