A spinner has 6 equally divided sections labeled A, B, C, D, E and F. After spinning the spinner, a number cube is rolled. What is the probability that the spinner will land on a consonant and the number cube will land on a number greater than 2?

Step-by-step explanation:

Given

The spinner has 6 equal sections A, B, C, D, E, and F

The two events occurred one after the other. So, the probability is the product of the probabilities of each event.

There are two consonants in the given 6 letter

The probability of landing over a consonant  is

The number greater than 2 in a cube are 3,4,5,6

So, probability corresponding to it

So, the required probability is

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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