In the sum of two numbers is 20 and their difference is 10 find the numbers​

"The sum of two numbers is 20" can be translated mathematically into the equation:

x + y = 20.

"... and their difference is 10" can be translated mathematically as:

x - y = 10

We can now find the two unknown numbers, x and y, because we now have a system of two equations in two unknowns, x and y. We'll use the Addition-Subtraction Method, also know as the Elimination Method, to solve this system of equations for x and y by first eliminating one of the variables, y, by adding the second equation to the first equation to get a third equation in just one unknown, x, as follows:

Adding the two equations will eliminate the variable y:

x + y = 20

x - y = 10

2x + 0 = 30

2x = 30

(2x)/2 = 30/2

(2/2)x = 15

(1)x = 15

x = 15

Now, substitute x = 15 back into one of the two original equations. Let's use the equation showing the sum of x and y as follows (Note: We could have used the other equation instead):

x + y = 20

15 + y = 20

15 - 15 + y = 20 - 15

0 + y = 5

y = 5

CHECK:

In order for x = 15 and y = 5 to be the solution to our original system of two linear equations in two unknowns, x and y, this pair of numbers must satisfy BOTH equations as follows:

x + y = 20 x - y = 10

15 + 5 = 20 15 - 5 = 10

20 = 20 10 = 10

Therefore, x = 15 and y = 5 is indeed the solution to our original system of two linear equations in two unknowns, x and y, and the product of the two numbers x = 15 and y = 5 is:

xy = 15(5)

xy = 75

191 students play sports and ninety-seven 10th graders were surveyed.

step-by-step explanation:

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%