One of the legs of a right triangle measures 14cm and its hypotenuse measures 15cm. Find the measure of the other leg

the measure of the missing leg is 5.38

or 5.4

Step-by-step explanation:

s is for Squared

Cs= As+Bs

let's say 14cm was side a

Bs=Cs-As

Bs= 15s-14s

Bs=225-196

Bs=29

B= square root of Bs

B=5.38

5.4

Step-by-step explanation:

c² = a² + b²

15² = 14² + b

225 = 196 + b

b = 225 - 196

= 29

= 5.4

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!