A long jumper leaves the ground at an angle of 20 degrees above the horizontal, at a speed of 9 m/s. The height of the jumper can be modeled by h(x)=-0.0048x^2+0.364x, where h is the jumpers height in meters and x is the horizontal distance from the point of launch

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

8.3 and the 3 is repeating

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i don't see any steps below, sweetheart