A projectile is launched
launched straight up in the air. Its height (in feet)t seconds after launch is given by the function f(t) = - 1612 +317t + 6. Find its velocity 3.7 seconds after it

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

i think it’s c i believe

  lol