At an amusement park, the probability that a child eats popcorn and cotton candy is 0.48. The probability that a child eats popcorn is 0.79, and the probability that a child eats cotton candy is 0.83. What is the probability (rounded to the nearest hundredth) that a child eats cotton candy
given that the child has already eaten popcorn?
P(ANB)
Hint: P(AB)
P(B)
0.38
0.58
0.40
0.61

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

c(x)= 6x + 3

step-by-step explanation: