Need Help Need Help Pls Part A: Create a scatter plot to represent the data shown above. Sketch the line of best fit. Label at least three specific points on the graph that the line passes through. Also include the correct labels on the x-axis and y-axis. Part B: Algebraically write the equation of the best fit line in slope-intercept form. Include all of your calculations in your final answer. Part C: Use the equation for the line of best fit to approximate the weight of the little girl at an age of 14 years old.​

Step-by-step explanation:

PART A

Remember Scatter plot is a type of x-y graph

X is the horizontal line and will be the AGE

Y is the vertical lien and will be WEIGHT

PART B

Slope-intercept form is y = mx + b

m is the slope of the line, determined by calculating "change of y divided by change of x"

Age 2 and weight 32 would be the point (2, 32) on the graph

Age 8 and weight 60 is the point (8, 60) in the graph

to calculate slope solve m =  60-32 =

8-2

b is the y-intercept or the place on the graph where the line crosses the vertical line (y-axis)

Calculate b by plugging in one of the graph points (i.e (2, 32)) into the slope-intercept form along with the value of m you just calculated.

32 = m(2) + b   plug in your calculated value for m to solve for b

once you have solved for m and b, put those number into the equation y = mx + b

PART C

Once you have the slope-intercept form, you can solve the equation for y (weight of the girl), but plugging in 14 for x (since that is her age).

i.e. if the equation was y = 50x + 100

y = (50 * 14) + 100 = 650 -- which is an unrealistic weight for the girl but a good example on how to solve problem.

c) yes, because of asa or aas