In this activity, you will use a variable to create expressions for various relationships. Then you will use these expressions to form a linear equation. Finally, you will find the solution to the equation. Theresa has two brothers, Paul and Steve, who are both the same height. Paul says he is inches shorter than times Theresa’s height. Steve says he is inches shorter than times Theresa’s height. If they are both right, how tall is Theresa?

To solve a problem like this one, you can use a linear equation where the variable represents Theresa’s height in inches. Let represent Theresa’s height in inches.

Question 1
The relationships for Paul’s and Steve’s height with respect to Theresa’s height are described above. First you will write expressions for Paul’s height and for Steve’s height. Then you will relate the expressions.

Part A
Write an expression to represent Paul’s height in inches.

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x