Mathematics, 05.05.2021 03:20, Drea1385
The hyperbolic cross section of a cooling tower is given by the equation 4x^2-y^2 + 16y-80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axls represents the ground surface. The diameter at the center of the tower is (__) meters. The center of the tower is (__) meters above the ground. Please help, taking semester exam and need help badly!!!
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The hyperbolic cross section of a cooling tower is given by the equation 4x^2-y^2 + 16y-80 = 0. The...
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