a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5 bills was 10 more than 4 times the amount of $10 bills. the register contained as many $1 bills as $5 bills and $10 bills combined, and two $50 bills. how many bills of each kind did the register contain?

9514 1404 393

Step-by-step explanation:

Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us ...

  a +5b +10c +50d = 685 . . . . . total amount of cash

  b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

  a = b+c . . . . . . . . . . . as many ones as fives and tens combined

  d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

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Substituting for 'a', then for 'b', we have ...

  (b+c) +5b +10c +50d = 685

  6(10 +4c) +11c +50d = 685

  60 +35c +50d = 685

Substituting d=2 and subtracting 160 gives ...

  35c = 525

  c = 15

  b = 10 +4c = 10 +4(15) = 70

  a = b+c = 70 +15 = 85

The register contained ...

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)