Jude says that the volume of a square pyramid with base edges of 7 in and a height of 7 in is equal to the volume of a cylinder with a radius of 7 in and a height of 7 in. Jude rounded all answers to the nearest whole number. Examine Jude's calculations. Is he correct? Volume of Square Pyramid Volume of Cylinder
V = B(h) V = r2h
V = 49(7) V = (72)(7)
V = 343 in3 V = 343 in3

D) No, he made a mistake in solving for the volume of both figures

Step-by-step explanation:

volume (Pyramind) = 1/3(Base area) hight

= 1/3 (7×7)×7

= 343/3 in³

volume (Cylinder)= πr²h

= 3.14(7)²×7

=3.14×343

= 31077.02 in³

So option D is your answer

hope it helps..

have a great day!!

the axial of symmetry

step-by-step explanation:

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)