What are the zeros of y = x^2 + 9x +14?

Step-by-step explanation:

obtain zeros P(x)=x  2

+9x+14

→ for zeros find P(x) = 0

x  

2

+9x+14=0

x  

2

+7x+2x+14=0

x(x+7)+2(x+7)=0

(x+7)(x+2)=0

x=−7 or x=−2

zeros is -7 & -2

→P(−7)=(−7)  

2

+9(−7)+14

=+49−63+14

=0

→P(−2)=(−2)  

2

+9(−2)+14

=4−18+14

=0

x= -7,x= -2

The zerores of polynomial y are -2 & -7

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

the 3rd on is correct

step-by-step explanation: