Part 5: Identify key features and graph a hyperbola from general form. Answer the following questions to determine the key features of the hyperbola based on the equation

shown, and then graph it.

4x^2 + 8x – 9y^2 – 36y – 68 = 0

a) Write the standard equation of the hyperbola. (3 points)
b) What is the center of the hyperbola? (1 point)
c) What are the foci of the hyperbola? (2 points)
d) What are the asymptotes of the hyperbola? (2 points)
e) Sketch a graph of the hyperbola and label the center, foci, guiding box, and asymptotes. (4 points)

n

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116