A crate weighing 500 pounds was delivered to the gym & set on the floor. To move it, we need to get a set of dolly wheels under the edge. If we use a 15 foot
pry bar to lift the edge and place a 12 high fulcrum back 2 feet from the box,
how much downward force will need to be applied to the bar to raise the crate?

4x and 6y

im not sure though

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

it’s the first one your welcome