What is the radius of (x+5)^{2}+(y-4)^{2}=121?

11

Step-by-step explanation:

Step-by-step explanation:

The figure drawn is a circle.  It's center is a (-5,4) just the opposite of what is in the brackets.  I'm giving you this information just to be complete.

For a circle the radius is found using the lone number on the other side of the equal side -- in this case 121

The radius is the square root of that lone number.  

radius^2 = 121

sqrt(radius^2) = sqrt(121)

radius = 11

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1

the correct answer is c

good luck love