3x+4y+z=-2
2y+3z=-8
z=-3

z=-3 so 2y+3(-3)=-8, 2y-9=-8, add 9 to both sides 2y=1 divide both sides by 2, y=1/2, so 3x+4(1/2)+-3=-2, 3x+2-3=-2, 3x-1=-2, add 1 to both sides, 3x=-1, divide both sides by 3, x=-1/3

y = 1/2

x = -1 / 3

z = -3

Step-by-step explanation:

In this question, in order to find "y" and "x", we do the following...

Since we know z = -3 we can find "y" by substituting z in the second equation.

2y + 3z = -8

2y + 3(-3) = -8

2y - 9 = -8

2y = 1

y = 1/2

Now we know "y" and "z" and so we can find x...

3x + 4y + z = -2

3x + 4(1/2) - 3 = -2

3x + 2 - 3 = -2

3x = -1

x = -1 / 3

9x