If a projectile is fired with an initial speed of v0 ft/s at an angle above the horizontal, then its position after t seconds is given by the parametric equations x = (v0 cos())t y = (v0 sin())t − 16t2 (where x and y are measured in feet). Suppose a gun fires a bullet into the air with an initial speed of 1920 ft/s at an angle of 30° to the horizontal. (a) After how many seconds will the bullet hit the ground? (in seconds)
(b) How far from the gun will the bullet hit the ground? (Round your answer to one decimal place.) (in miles)
(c) What is the maximum height attained by the bullet? (Round your answer to one decimal place.) (in miles)

b. x- 48 =120

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!

3

step-by-step explanation: