suppose that the number of bacteria in a certain laboratory colony grows at the rate of 5% per day. if there are 1000 bacteria present initially, then that will be the number of bacteria present after 2days?​

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

hit or miss i guess they never miss huh

step-by-step explanation:

you got a boyfriend i bet he doesnt kiss ya

12.4, 12.387, 12.26, 12.252, 6.241, 6.2, 6.015, 6.009, 1.411, 1.2, 1.056, 1.007, 0.31,   0.13, 0.5, 0.04

step-by-step explanation:

ur welcome : )