The zeros of a quadratic function are -7 and 3. Which of the following could be the function? Select all that apply. A. F(x)=2x^2-8x-42
B. F(x)=5x^2+20x-105
C. F(x)=x^2+4x-21
D. F(x)=x^2-4x-21

step-by-step explanation:

if x = 2 you have to find x to finish the problem

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

a

step-by-step explanation: