Match each transformation of function fwith a feature of the transformed function. domain of (0,0)
x-intercept of (-2,0)
vertical asymptote of I = 3
range of (-3,00)
h(x) = 35(1) – 3
9() = -f(x - 3)
j(x) = f(x + 3)
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for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

step-by-step explanation: