The equation of a parabola is 1/16(y+3)^2 = x + 4.
What are the coordinates of the focus?
•...
Mathematics, 29.04.2021 01:00, kidward
The equation of a parabola is 1/16(y+3)^2 = x + 4.
What are the coordinates of the focus?
• (-4, 1)
• (-8, -3)
• (-4, -7)
• (0, -3)
Answers: 3
Mathematics, 21.06.2019 12:50, 2022mcwhirterbrendan
Solve the system by the elimination method. 2x + y - 4 = 0 2x - y - 4 = 0 when you eliminate y, what is the resulting equation? a. x = 0 b.4x = -8 c.4x = 8
Answers: 1
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