Mathematics, 28.04.2021 19:40, nananna90

For 0° < x < 360°, what are the solutions to cos(x/2)- sin(x)=0 ? O {0°, 60°, 300°)
O {0°.120°, 240°}
O {60°, 180°, 300°}
O {120°,180°, 240°}

For 0° < x < 360°, what are the solutions to cos(x/2)- sin(x)=0 ?

O {0°, 60°, 300°)
O {0°.1

Answers: 2

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For 0° < x < 360°, what are the solutions to cos(x/2)- sin(x)=0 ? O {0°, 60°, 300°)
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For 0° < x < 360°, what are the solutions to cos(x/2)- sin(x)=0 ? O {0°, 60°, 300°) O {0°.120°, 240°} O {60°, 180°, 300°} O {120°,180°, 240°}

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For 0° < x < 360°, what are the solutions to cos(x/2)- sin(x)=0 ? O {0°, 60°, 300°)
O {0°.120°, 240°}
O {60°, 180°, 300°}
O {120°,180°, 240°}