Suppose an airplane is flying 180 mph with a heading 25° east of south (295° measured counterclockwise from due east) when it encounters a 35 mph wind blowing steadily in a direction 15° north of east (15° measured counterclockwise from due east). Use →v to represent the speed vector of the airplane and →w to represent the speed vector of the wind. Start by drawing a head-to-tail configuration for →v and →w and the resultant vector →v+→w.

Write both →v and →w in component form. (Your answers should be in the form "< #, # >".)

→v=

→w=

Write the resultant vector →v+→w in component form.
→v+→w=

Now, write the resultant vector →v+→w in polar form. (You do not need to enter a degree symbol in your answer.)
→v+→w=

Your answer to part (c) tells us that the plane is actually moving at _ mph in the direction_  ° counterclockwise of due east.

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step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

hi there!

the answer will be d: 2

hi how are you doing today? if you ever need just tell me

step-by-step explanation: