Two copier machines in the ISE department are maintained by a single repairman, Justin. Machine i functions for an exponentially distributed amount of time with rate i before it breaks down. The repair times for copier i are exponential with rate i. The repairman can only work on one machine at a time. Because machine 1 is more important than machine 2, so that the repairman will always work on machine 1 if it is down, regardless of the state of machine 2. (In case machine 2 is currently being repaired by the repairman when machine 1 fails, the repairman will instantaneously switch to machine 1. The repair of machine 2 will resume later.) Required:
a. Formulate a Markov chain model for this situation with state space {0, 1, 2, 12, 21).
b. Suppose that λ 1-1, μ1-2, A2-3, μ2-4. Find the stationary distribution.

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)

40 i don’t know lololol