Which probabilities are correct? Select two options. P(A|C) = Two-thirds
P(C|B) = StartFraction 8 Over 27 EndFraction
P(A) = StartFraction 31 Over 59 EndFraction
P(C) = Three-sevenths
P(B|A) = StartFraction 13 Over 27 EndFraction

idn

step-by-step explanation:

the first option is the answer.

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

2 pecks

step-by-step explanation: