Which of the following sets of ordered pairs is a functionB {
(
8
,
1
)
,

(
7
,
0
)
,

(
7
,
−
1
)
,

(
8
,
2
)
}
{
(
8
,
1
)
,

(
7
,
0
)
,

(
7
,
−
1
)
,

(
8
,
2
)
}

C
{
(
6
,
1
)
,

(
7
,
3
)
,

(
4
,
2
)
,

(
6
,
2
)
}
{
(
6
,
1
)
,

(
7
,
3
)
,

(
4
,
2
)
,

(
6
,
2
)
}

D
{
(
1
,
3
)
,

(
2
,
4
)
,

(
−
1
,
−
3
)
,

(
−
2
,
−
4
)

your answer is

a.

5

step-by-step explanation:

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7

the answer to 1/4x+5/3x-4=2-1/12x is x=3

hope this if needed hmu

its four gallons, i took the test and this was right.

step-by-step explanation:

on the dot where it starts for four gallons, that's when it doesn't move up any more.