What are the solutions of 3x^2 +6x +15 =0

Step-by-step explanation:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

3

2

+

6

+

1

5

=

0

3x^{2}+6x+15=0

3x2+6x+15=0

=

3

a={\color{#c92786}{3}}

a=3

=

6

b={\color{#e8710a}{6}}

b=6

=

1

5

c={\color{#129eaf}{15}}

c=15

=

−

6

±

6

2

−

4

⋅

3

⋅

1

5

√

2

⋅

3

x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{3}} \cdot {\color{#129eaf}{15{2 \cdot {\color{#c92786}{3}}}

x=2⋅3−6±62−4⋅3⋅15

2

b

step-by-step explanation:

the word superfluous means unnecessary

answer is x<