The weights of 5 girls are 70 pounds, 68 pounds, 85 pounds, 62 pounds, and 70 pounds. Nina finds measures of center and measures of variation of this data. Match the descriptions to the type of measure. She found the difference of the least
and the greatest values.

She added all the values and divided the
sum by 5.

She found the mean and then
found the average deviation of
the weights from the mean.

She found the difference of the
upper quartile and the lower
quartile.

She found the value that appeared the
most often.

She found the middle value after
arranging all the values from least
to greatest.

Item 1 solve for s. s+24=90 −114 −66 66 114

Which property was used to simplify the expression? 3c+9 +4c=3c+4c+9

Apoll is being conducted at a mall nothingto obtain a sample of the population of an entire country. what is the frame for this type of​ sampling? who would be excluded from the survey and how might this affect the results of the​ survey? what is the frame for this type of​ sampling? a. the frame is people who need new clothes. b. the frame is people who shop at the mall. c. the frame is people who like to shop. d. the frame is the entire population of the country. who would be excluded from the survey and how might this affect the results of the​ survey? a. any person that does not need new clothes is excluded. this could result in sampling bias due to undercoverage. b. any person who does not shop at the mall is excluded. this could result in sampling bias due to undercoverage. c. any person who does not shop at the mall is excluded. this could result in nonresponse bias due to people not participating in the poll. d. there is nobody that is being excluded from the survey.