A ball is thrown into the air from a height of 4 feet at time t=0. The function models this situation is h(t)=16t^2=63t+4 where t is measured in seconds and h is the height in feet. When will the ball reach a height of 50 ft

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!