PLZ HELP ASAP BRANILIEST Seven hundred people are gathered in a trapezoidal park with bases measuring 50 yards and 90 yards and a height of 50 yards. Find the population density of the park.

The population density of the park is people per square yard.

Find the population density if the bases and height are halved.

The population density of the park if the bases and height are halved is
people per square yard.

0.2, 0.8

Step-by-step explanation:

The area of the park is 0.5h(b1 + b2), where h is the height, b1 is the first base, and b2 is the other base.

Plug the values in:

Area = 0.5(50)(50+90) = 0.5(50)(140) = (50)(70) = 3500

Since 700 people are in the park, there is 700/3500 = 0.2 people per square yard.

If the bases and height are halved, the new area is:

Area = 0.5(25)(25+45) = (35)(25) = 875

The new population density is 700/875 = 0.8 people per square yard.

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3