Help!!!

Calculate tan(4π3).

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The tangent function has a period of π units. That is,

tan(x+nπ)=tanx

for all n∈Z.

Since 4π3=π3+π, we can rewrite the original expression tan(4π3) as follows:

tan(4π3)=tan(π3+π)

=tan(π3)

=sin(π3)cos(π3)

=(3√2)(12)

=3–√3

Hence,

tan(4π3)=3–√3

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)