As bridge building, craftily clever Calpurnia does dazzlingly double-duty dinners, emcee-ing elegant, elegiac, eleemosynary events: for forty-four favorite uffy fat-cats, Georgia'sgolden girl gladly helps heavy hitters initiate inimitable joviality. In Calpurnia's experi-ence the population of all her donations is approximatelyNormally distributed. TonightCalpurnia's 44 fat-cats donate $27,500, with Standard Deviations s= $125. Required:
a. Estimate the mean donation for Calpurnia's population of fat-cats.
b. To draw any inferences from these data, what must we assume about the population of fat-cat donations, and why? We shall assume this for the remainder of this problem.
c. For Calpurnia's sample of 45 donors, suppose that s = $120.

i. Find a 90% confidence interval for Calpurnia's population mean donation.
ii. Find a 98% confidence interval for Calpurnia's population mean donation.
iii. Compare your answers in c. i. and c. ii.: which interval is wider, and why?

d. Calpurnia believes she can rake in more than $400 per party-goer, on average. What hypotheses should she use to test this? Define in words any parameters.
e. To test these hypotheses, what test-statistic should Calpurnia use?

since both sides equal, there are infinitely many olutions.

1. 22

2. 1

3. 7

4. 18

step-by-step explanation

e2020 got it right

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet