A standard number cube, labeled numbers 1-6 on each side, is rolled three times. Mary says the chance of rolling a 2 all three times is 1/8. But John disagrees and says the probability for rolling a 2 all three times is 1/216. Who calculated the correct probability or rolling a 2 the three times the n number cube is rolled? Show work to justify your reasoning.

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

the answer is simply just 6n add the two together as they have an n