What are the steps for using a compass and straightedge to construct a line through point P that is parallel to line m? Drag the steps and drop them in order from start to finish. Place the point of the compass on point X and draw an arc that intersects lines m and n. Label the intersections as points A and В. Place the point of the compass on point A and open it to width AB. Without changing the width of the compass opening, place the point of the compass on point Pand draw an arc that intersects line n. Label the intersection as point o. With the compass opening set to width AB place the point of the compass on point C and draw an arc that intersects the arc that was drawn from point P. Label the intersection of the arcs as point Y. Use the straightedge to draw a line n that passes through Pana intersects line m. Label the point of intersection as point X​

the answer to this question is 3/19

step-by-step explanation:

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb