What are the solutions to the equation? x^2−14x=15

The solutions to the equation are 15 and -1.

x = 15 and x = -1

Step-by-step explanation:

x^2 - 14x = 15

Subtract 15 from both sides:

x^2 - 14x -15 = 0

a = 1, b = -14, c = -15

Use the quadratic formula:

[-(-14) ± √-14^2 - 4(1)(-15)]/2(1)

[14 ± √196 - (-60)]/2

(14 ± √256)/2

(14 ± 16)/2

(14 + 16)/2 = 30/2 = 15

(14 - 16)/2 = -2/2 = -1

x = 15 and x = -1

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length