Use the function f(x) = 2x2 − 3x − 5 to answer the questions. Part A: Completely factor f(x). (2 points)

Part B: What are the x-intercepts of the graph of f(x)? Show your work. (2 points)

Part C: Describe the end behavior of the graph of f(x). Explain. (2 points)

Part D: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part B and Part C to draw the graph. (4 points)

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Step-by-step explanation:

2x^2-3x-5=y

(2x-5)(x+1)=y

(2x-5)(x+1)=0

2x-5=0

2x=5

x=2.5

x+1=0

x=-1

you have an even degree (2) and a positive coefficient (2)

therefore as x---> -∞, f(x)> +∞

also, as x> +∞, f(x)> +∞

also notice that this is a parabola that opens upwards so both "ends" approach positive infinity

plot the x-intercepts, find the vertex using h=-b/2a and substituting this value into the equation to find k and make a table of values to graph the parabola unless you only want a rough sketch of the graph-you know the x-intercepts and you found the vertex using h=-b/2a

is only a line? i think so