1. What is the equation of a circle with center (2, 5) and radius 7? A. (x - 2)² + (y – 5)2 = 7
B. (x + 2)2 + (y + 5)2 = 7
C. (x - 2)2 + (y – 5)2 = 49
D. (x + 2)+ (y + 5)2 = 49​

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

answer: the is put the 450

step-by-step explanation: