the focus of a parabola is located at (0,2) the directx of the parabola is presented by y =2 which equation represents the parabola y^2=-2x x^2=-2y y^2=-8x x^2=-8y​

sorry i need the points

step-by-step explanation:

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answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.